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X^2+35X-10200=0
a = 1; b = 35; c = -10200;
Δ = b2-4ac
Δ = 352-4·1·(-10200)
Δ = 42025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42025}=205$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-205}{2*1}=\frac{-240}{2} =-120 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+205}{2*1}=\frac{170}{2} =85 $
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